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os.access()
阅读量:496 次
发布时间:2019-03-07

本文共 763 字,大约阅读时间需要 2 分钟。

概述

  os.access() 方法使用当前的uid/gid尝试访问路径
  大部分操作使用有效的 uid/gid, 因此运行环境可以在 suid/sgid 环境尝试

语法

  os.access(path, mode)

参数path

    要检测是否有访问权限的路径
    path结尾不能有"\",具体如下:
    C:/tmp/foo.txt --> OK
    C:/tmp --> OK
    C:/tmp/ --> 报错mode
    mode为F_OK,测试存在的路径,或者它可以是包含R_OK, W_OK和X_OK或者R_OK, W_OK和X_OK其中之一或者更多。
    os.F_OK: 测试path是否存在
    os.R_OK: 测试path是否可读
    os.W_OK: 测试path是否可写
    os.X_OK: 测试path是否可执行

返回值

  True:路径存在,或者路径有相应的读写执行权限
  False: 与之相反使用示例

# -*- coding: UTF-8 -*-import os, sys# 假定 C:/tmp/foo.txtt 文件存在,并有读写权限ret = os.access(r"C:/tmp/foo.txt", os.F_OK)print(ret) #输出:Trueret = os.access(r"C:/tmp/foo.txt", os.R_OK)print(ret) #输出:Trueret = os.access(r"C:/tmp/foo.txt", os.W_OK)print(ret) #输出:Trueret = os.access(r"C:/tmp/foo.txt", os.X_OK)print(ret) #输出:False

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